You first want to determine the characters. Since every element is of the form $aI+bE$, with $E$ nilpotent, it is easy to check that the only character is the map $\varphi:aI+bE\longmapsto a$. Indeed, write $\gamma=\varphi(E)$. Then $$ \varphi(aI+bE)=a+b\gamma. $$ For this to be multiplicative, we need \begin{align} \gamma^2&=\varphi\left(E\right)^2=\varphi (E^2)=\varphi (0)=0. \end{align} This forces $\gamma=0$, so $\varphi(aI+bE)=a$.
Now the Gelfand transform is the map $\Gamma:A\to C(\\{\phi\\})=\mathbb C$, with $$ \Gamma(aI+bE)(\varphi)=\varphi(aI+bE)=a. $$