Divide the ten nights as follows:
1 2 | 3 4 | 5 6 | 7 8 | 9 0
Since we have five pairs of nights but 61 hours of sleep, by the pigeonhole principle there must be at least one pair of nights with $\left\lceil\frac{61}5\right\rceil=13$ or more hours of sleep. This proves the statement.