Since $\mathbb{N}$ is separable (with the discrete topology), we have that $\mathbb{N}^{{\mathbb{N}}}$ is separable with the product topology. Therefore, any subspace is separable, so there is no discrete subspace of cardinal $2^{\aleph_{0}}$
Since $\mathbb{N}$ is separable (with the discrete topology), we have that $\mathbb{N}^{{\mathbb{N}}}$ is separable with the product topology. Therefore, any subspace is separable, so there is no discrete subspace of cardinal $2^{\aleph_{0}}$