Let $x$ and $y$ be the _purchase prices_ of the two bicycles respectively. The profit in the first case then is
$p_1=(1.1-1)x+(1.2-1)y=0.1x+0.2y$
$1.1x$ and $1.2y$ are the _selling prices_.
The profit in the second case is
$p_2=(1.2-1)x+(1.1-1)y=0.2x+0.1y$
$p_2$ is $RS \ 5$ greater than $p_1$. Therefore $p_2=p_1+5$. It follows
$0.2x+0.1y=0.1x+0.2y+5 \quad (1)$
And the sum of x and y is 1600:
$x+y=1600 \quad (2)$
By using (1) and (2) you can calculate $x$ and $y$.