When the bobbin rolls one complete turn to the right, it has travelled $10\pi$ cm. So the center of the inner reel has also travelled that distance. The amount of thread in one turn around the inner reel is $5 \pi$ cm. So assuming that the thread is coming off the top of the inner reel, the end of the thread has moved $10 \pi$ cm + $5 \pi$ cm = $15 \pi$ cm. So: for $10\pi$ cm of movement of the bobbin, we get $15 \pi$ cm of movement of the thread-end. That's a ratio of 3 to 2.
When the thread has moved 12cm, the bobbin must have moved $8$cm.
**Note:** it's also possible for the thread to come off the _bottom_ of the bobbin, and in this case, $10\pi cm$ movement of the bobbin causes only $10 \pi - 5\pi$ = $5 \pi$ cm movement of the thread, i.e., a ratio of 1 to 2. So that when the thread has moved $12cm$, the bobbin must have moved $24$cm (i.e., your answer).
The question is fundamentally ambiguous.