Your differential equation initial value problem is given as $y'=f(t,y)$, $y(t_0)=y_0$.
For the multistep method the first computable value is $y_2$. However, to compute that you also need $y_1$ which can not be computed via the multistep method and thus needs some other method to provide that value.
Note that if the multi-step method has error order $p$, then the initialization method should have at least error order $p-1$ so that the propagation of these initial local errors does not contribute a worse order term to the global error.