Notice that
$$u=(a,b,c)\in W\iff u=(a,b,-a-b)=a(1,0,-1)+b(0,1,-1)\in S$$ where
$$S=\operatorname{Span}((1,0,-1),(0,1,-1))$$ so $W=S$ which is a subspace of $\Bbb R^3$ of dimension $2$.
Notice also that using the linear form $\varphi:\Bbb R^3\to\Bbb R,(a,b,c)\mapsto a+b+c$, we see that $W$ is nothing but the kernel of $\varphi$ and its dimension is 2 due to the rank-nullity theorem.