This is not a Monty Hall situation, since the events of the first two days were _not_ guaranteed to turn out that way - in the original Monty Hall the host-opened door is guaranteed to have a zonk. There is also no initial choice of which day is the special one (will have the alarm go off then), something which happens in Monty Hall with the initial choice of door by the player.
Accordingly, the probability that the alarm goes off on Wednesday _given_ that the first two days had no alarm is raised to $\frac15$. Formally: $$P(\text{alarm goes on Wednesday}|\text{alarm doesn't go off on Monday or Tuesday})=\frac{1/7}{5/7}=\frac15$$