Is ';;' a chaining operator in Unix? How does it work? My teacher lists the following chaining operators: & && ( ) ; ;; | || new line How is ;; a chaining operator and what does it do?

Your teacher will probably talk later on about `case` statements in `bash` and how each option statement is closed by `;;`.

As in:


case $space in
[1-6]*)
Message="All is quiet."
;;
[7-8]*)
Message="Start thinking about cleaning out some stuff. There's a partition that is $space % full."
;;
9[1-8])
Message="Better hurry with that new disk... One partition is $space % full."
;;
99)
Message="I'm drowning here! There's a partition at $space %!"
;;
*)
Message="I seem to be running with an nonexistent amount of disk space..."
;;
esac


See TLDP Bash Guide for Beginners - 7.3. Using case statements