That's a good question. An answer is that there are many probability spaces $(\Omega,\mathcal{A},p)$ where the probability function $p$ cannot be extended to all of $\mathcal{P}(\Omega)$. For example, consider the probability space where $\Omega=[0,1]$, $\mathcal{A}$ is the Lebesgue $\sigma$-algebra on $[0,1]$, and $p=\lambda$ is the Lebesgue measure. Then there is no way of extending $p$ to have a value when given the Vitali set (the standard example of a non-Lebesgue measurable subset of $[0,1]$).