Let $I$ be an ideal of $\mathbb{T}$. If $I$ contains a real $r$, then it contains every real $s$ since $s = r + (s-r)$. Moreover, it contains $-\infty$ since $r + (-\infty) = -\infty$. Thus $I = \mathbb{T}$. It follows that $I = \\{-\infty\\}$ is the unique proper ideal of $\mathbb{T}$. Indeed, it is closed under $\min$ and, for every $r \in \mathbb{T}$, $r + (-\infty) = -\infty$.