Since
$$\text{Amount remaining} =\text{Original Amount} \times \bigg(\frac{1}{2}\bigg)^{\text{number of half lives}} $$
solve for $X$ in the equation
$$10 = X \times \bigg(\frac{1}{2}\bigg)^{\frac{1000}{1590}}$$
Since
$$\text{Amount remaining} =\text{Original Amount} \times \bigg(\frac{1}{2}\bigg)^{\text{number of half lives}} $$
solve for $X$ in the equation
$$10 = X \times \bigg(\frac{1}{2}\bigg)^{\frac{1000}{1590}}$$