Hint: Things are symmetric for positive and negative $x$ and $y$, so just assume $x\ge 0$ and $y \ge 0$ and solve the problem. Then each solution where $x$ and $y$ are nonzero gives four solutions, each solution where exactly one is zero gives two, and the origin (if it were a solution, which it is not here) gives one. For the last max, just do the cases. Assume $\frac x{\sqrt 3} \gt y$, solve, and check that the solution meets the assumption, then assume the other way.