$V$ as initial value of the dollar, decreases approximately one half: $V_{n+1}\approx\frac{1}{2}V_n$ every $5$ years.
$V$ at first.
$\frac{1}{2}V$ after $5$ years.
$\frac{1}{4}V$ after $10$ years.
$\dots$
After $5n$ years:
$$ V\approx\frac{1}{2^{n}}V_0$$
Now for one-millionth solve:
$1/2^n=1/1000000$
$2^n=1000000$
$n\approx19.9316$
Thus the answer is after $\approx100$ years which is a rough rounded estimate.