A biconditional, say, $K \longleftrightarrow N\equiv (K \rightarrow N) \land (N\rightarrow K)$ is true only when both $K$ and $N$ are true, or when both $K$ and $N$ are false.
However if one is true and the other false, the biconditional is not true. Hence, it is not true for all truth-value assignments for $K, N$. Hence, it is not a tautology.
We do have that $K \iff N \equiv (K\; \text{ XNor } N)$ and shares the following truth-table:
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