If the cdf is $F_X(x)$, then $$\Pr(X\le b)=F_X(b)$$ and $$\Pr(a
The exponential cdf is $F_X(x)=1 − e^{-\lambda x}$. You can substitute the $\le$ with $<$, since the cdf is continuous.
If the cdf is $F_X(x)$, then $$\Pr(X\le b)=F_X(b)$$ and $$\Pr(a
The exponential cdf is $F_X(x)=1 − e^{-\lambda x}$. You can substitute the $\le$ with $<$, since the cdf is continuous.