Quadratic problem NASA launches a rocket at $t = 0$ seconds. Its height, in meters above sea-level, as a function of time is given by $h(t) = -4.9t^2 + 37 t + 101$. Assuming that the rocket will splash down into the ...--prophetes.ai

Quadratic problem NASA launches a rocket at $t = 0$ seconds. Its height, in meters above sea-level, as a function of time is given by $h(t) = -4.9t^2 + 37 t + 101$. Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? How high above sea-level does the rocket get at its peak? ### Progress I figured that it will splash down after 9.68032 seconds. I don't know how to find it's peak though.

Hint: The x-coordinate of the vertex (peak) of any quadratic equation $ax^2 + bx + c = 0$ is $\frac{-b}{2a}$. By inputting this value into your function, you can find the y-coordinate of the vertex (peak)