The vector $\alpha$ belongs to $V$. Your remark would be correct if we were assuming that $\alpha\in W$. In particular, if $\alpha\in W$, $S_T(\alpha;W)$ is indeed the set of all polynomials.
The vector $\alpha$ belongs to $V$. Your remark would be correct if we were assuming that $\alpha\in W$. In particular, if $\alpha\in W$, $S_T(\alpha;W)$ is indeed the set of all polynomials.