Is this formula: $81n^2+135n+97$ wealth by prime numbers which $n$ is natural number? I made some effort to set a wealth quadratic formula for prime, I found this formula: $A(n)= 81n^2+135n+97$, it gives primes for $n=0 $ to $n=18 $. I would be like some one to show me if this really a wealth quadratic formula for primes for large $n$? Thank you for any replies or any comments.

It gives primes for $26284$ of the integers from $1$ to $10^5$, so it's not too bad. Not quite as good from that point of view as $n^2 + n + 41$, which produces primes for $31984$ of those integers.

EDIT: your $A(n) = (9 n + 7)^2 + (9 n + 7) + 41$, so you just have a minor modification of the Euler polynomial.