Let $X$ be the number of dollars won by the house.
We know that $X \sim B\left(2500,\dfrac{10}{19}\right)$.
We can estimate it by $N(1316,623)$.
So, the required probability (using continuity correction):
$\begin{array}{cl} =&P(X \ge 99.5) \\\ =&P\left(Z \ge \dfrac{99.5-1316}{623} \right) \\\ =&P\left(Z \ge -1.9526 \right) \\\ =&P\left(Z \le 1.9526 \right) \\\ =&0.9744 \end{array}$