Artificial intelligent assistant

Mandelbrot precision target the center of a pixel? I read this question and I don't understand the answer: < Especially how can I aim for the center of the pixel like so: for(unsigned SX = SMin; x < SMax; ++x) { double k = (double(SX + 0.5) - SMin) / (SMax - SMin); double IX = (k * (IMax - IMin)) + IMin; } Is k then the real factor and ix the imaginary factor? I've made an example here: < but how can I find the corner pixel when I want to zoom into it like so: double Re_factor = (MaxRe-MinRe)/(ImageWidth-1); double Im_factor = (MaxIm-MinIm)/(ImageHeight-1); double newMinRe = MinRe + (Re_factor* x1); double newMaxRe = MinRe + (Re_factor* x2); double newMinIm = MinIm + (Im_factor* y1); double newMaxIm = MinIm + (Im_factor* y2); In my example the zoomed image is a bit tall in the y-axis. Why is this? Update: IX is the x-value in the imaginary space hence my first question is answered.

I would use Im_factor = Re_factor (assuming square pixels on your screen). In other words, $(MaxRe-MinRe):(MaxIm-MinIm)$ should equal $(ImageWidth-1):(ImageHeight-1)$.

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