The number of molecules emitted in a second has Poisson distribution, parameter $0.5$.
The probability of _at least one_ molecule is $1$ minus the probability of $0$ molecules.
The probability of $0$ molecules is $e^{-0.5}$.
For the $5$ second problem, use the fact that the number of molecules in a $5$ second interval has Poisson distribution with parameter (mean) equal to $(0.5)(5)$.
To find the probability of more than $3$ molecules, first find the probability of $3$ or fewer molecules. This will involve adding _four_ terms.