$S_t = S_0 + \mu t + \sigma^2 t^2\\\ S_1 = 2 + Z$
Z is a normally distributed random variable with standard deviation $\sigma = 0.5$
The option is in the money if $Z>0$ and out of the money of $Z\le 0$
The expected value $= \int_0^{\infty} x \frac {1}{\sigma\sqrt{2\pi}}e^{-\frac {x^2}{2\sigma^2}} dx$
$= \int_0^{\infty} \frac {2x}{\sqrt{2\pi}}e^{-2x^2} dx = \frac {1}{2\sqrt{2\pi}}$
I suppose there should be a NPV adjustment, as I pay today to exercise at $t=1$
$e^{-rt}\frac {1}{2\sqrt{2\pi}}$