What percent of Juan's income is Mary's income? For the following question > > Mary's income is 60% more than Tim's income , and Tim's income is 40% less than Juan's income. What percent of Juan's income is Mary's income? (Ans=96%) I am attempting to solve this using the following two equations, but I can't figure out what to do next. Suggestions would be appreciated Mary = Mary + $\frac{60}{100}Tim$ Tim= Tim - $\frac{40}{100}Juan$

**Example** : $A$ is 10% bigger than $B$ means that $A = (1 + 0.10)B = 1.10B$. And: $A$ is 10% less than $B$ means $A = 1 - 0.10 = 0.90B$.

**Example** : If I have $200$ apples and you have $300$ apples, then $300/200 = 1.50 = 1 + 0.50$, so you have $50$% more apples that I do. So that is $300 = 200 + 0.50\cdot 200$.

Let $M$ be Mary's income, $T$ be Tim's income, and $J$ be Juan's income. Then you have $M = 1.6T$ and $T = 0.6J$, so $M = 1.6\cdot 0.6J = ...$

As a sidenote: the equations that you wrote down don't really make sense. The first one, for example, would imply that Tim's income is zero (subtract Mary on both sides).