It is closed, If question has been stated correctly ! First note that when you write $f:\Bbb R^n \times \Bbb R^m \to \Bbb R$ this means $dom(f) = \Bbb R^n \times \Bbb R^m$. and since $f$ is convex on whole space it is continuous so is automatically closed (you don't need make this assumption)! In particular $f_{x_0} : \Bbb R \to \Bbb R$ with $f_{x_0}(y)=f(x_0,y)$ is convex and so it is closed!