$$4-\sqrt{3u_n+4}\le \frac 12 (4-u_n)\iff 4-\sqrt{3u_n+4}\le 2-\frac 12u_n\\\ \iff 2-\sqrt{3u_n+4}\le -\frac 12 u_n\iff 2+\frac12 u_n\le \sqrt{3u_n+4} \\\\\iff 4+2u_n+\frac14 u_n^2 \le 3u_n+4 \iff \frac14 u_n^2-u_n\le 0 \\\ \iff u_n\left(\frac14 u_n-1\right)\le0, $$ which holds since $0\le u_n <4.$