Suppose $1+uv$ is invertible, inverse $w$. Let your imagination run wild:
$1/(1+vu)= 1-vu+vuvu - vuvuvu + ... = 1 - v(1-uv + uvuv - ...)u = 1-vwu$
Now you can check $1-vwu$ really is inverse to $1+vu$.
There's a name for this trick; I have forgotten it but someone here will know.