It's the usual Legendre polynomial of order 2. But remember, that is usually on the interval $[−1,1]$, whereas the link you give is over $[0,1]$. So instead of $\pm \frac1{\sqrt 3}$ it is $\frac12(1\pm\frac1{\sqrt 3})$.
It's the usual Legendre polynomial of order 2. But remember, that is usually on the interval $[−1,1]$, whereas the link you give is over $[0,1]$. So instead of $\pm \frac1{\sqrt 3}$ it is $\frac12(1\pm\frac1{\sqrt 3})$.