An hour is two half hours. If the probability in each half hour is $p$, the probability not to see a falling star in the entire hour is $(1-p)^2=1-0.64=0.36$, so $1-p=0.6$ and $p=0.4$. Note that $0.64$ was chosen such that the square root could be easily drawn with or without taking complements, so you wouldn't have noticed if you hadn't taken complements.