Let the edges be the lines $OA$, $OB$, $OC$, $OD$. We may assume that $A$, $B$, $C$, $D$ are in the plane we project onto. If $O'$ is the projection of $O$ on their plane, then the cross-ratio of the projections is $O'A$, $O'B$, $O'C$, $O'D$.
So in plane our problem is the following: _are there four points A, B, C, D in the projective plane such that for all points O' in the plane the cross-ratio of lines (O'A, O'B, O'C, O'D) is constant_?
The answer is _no_. If we consider any points $A$, $B$, $C$, $D$, the cross-ratio $(O'A, O'B, O'C, O'D)$ equals to the cross-ratio of the intersections of these lines with any other line, for example $AB$. But considering any two points $\overline{C}$ and $\overline{D}$ in $AB$, if we choose $O':=C\overline{C}\cap D\overline{D}$, $(O'A, O'B, O'C, O'D)=(AB\overline{C}\overline{D})$. Since $\overline{C}$ and $\overline{D}$ are arbitrary points on $AB$, this cross-ratio can take any values, thus it cannot be constant.