To show that $F$ is not conservative on $\mathbb{R}^2 \setminus \\{ 0 \\}$, compute the curve integral of $F$ along the unit circle. It will turn out to be non-zero, which shows $F$ can't be conservative.
For b), the domain $\Omega$ is simply connected, so the fact that $\operatorname{rot}(F) = 0$ on $\Omega$ is enough to guarantee that $F$ is convervative here. (You can also compute a potential function if you'd like.)