Assume that we are working with angles in degrees.
Hint:
$$\cos(195) = \cos(180 + 15)$$
Another hint:
> Now split $\cos(180 + 15)$ using $\cos(A+B) = \cos(A)\cos(B)-\sin(A)\sin(B)$.
And another:
> Substitute $\sin(180) = 0$ and $\cos(180) = -1$.
Nearly done:
> Notice that $\cos(15) = \cos(30/2)$ and remember that $\cos(2A) = 2\cos^{2}(A) - 1$.
Now draw the 30/60/90 triangle and evaluate.