Presumably the probabilities you are given are disjoint. The $1$ in $10$ for getting a free ticket does not include the chance you match $3$ or more numbers. In that case you can just add the probabilities.
If they are not disjoint, the chance of getting $4$ or $5$ is included in the chance of $3$, so you can just use the chance of $3$ as the chance of getting cash. Similarly the chance of winning anything would be the chance of getting $2$.