The answer is _yes_ : If $1/s$ is algebraic, then $p(1/s) = 0$ for some nontrivial polynomial $$p(x) = a_0 x^0 + \cdots + a_n x^n$$ with rational coefficients. But then $$0 = s^n p(1/s) = a_0 s^n + \cdots + a_n s^0,$$ which implies that $s$ is algebraic.