To obtain the first blue ball on draw $x$ you need to select $x-1$ of the three red balls, and then one of the five blue balls; out of all the ways to select $x$ of the eight balls. $$\mathsf P_X(x) = \dfrac{\dbinom{3}{x-1}\dbinom{5}{1}}{\dbinom{8}{x-1}\dbinom{9-x}{1}}\cdot\;\mathbf 1_{x\in\\{0,1,2,3,4\\}}$$