I don't think one can use the binomial setting here, as the different choices corresponding to each wine are not pairwise independent (for instance, the last choice is totally determined by the first seven).
It's a problem of counting the number of permutations on a set of cardinality $n$ which have exactly $k$ fixed point (here $n=8$ and $k$ ranges from $5$ to $8$).
We have $P(X=k) = \frac{1}{k!}\sum_{i=0}^{n-k}\frac{(-1)^i}{i!}$
thus $P(X\ge 5)=\frac{1}{360}+\frac{1}{1440}+0+\frac{1}{40320}=\frac{141}{40320}$ if I'm not mistaken.