You only need to apply an impulse input (i.e. $x(n) = \delta (n)$), and see what is the response $y(n)$ (It is usually called $h(n)$). In this case, as the output does not depend on its self, you simply obtain: $$h(n) = \delta (n) + 2 \delta (n-2) - 2 \delta (n+2) $$ From this impulse response you can obtain the response for any input.