Multiply $ac=bd$ by $d$ and $ad+bc=0$ by $c$ then
$$bd^2+bc^2=b(c^2+d^2)=0$$
So, either $c=d=0$ or $b=0$. Take the second case then we get $ac=0$ and $ad=0$. So either $a=0$ or $c=d=0$. The second option brings us back to our first case.
Multiply $ac=bd$ by $d$ and $ad+bc=0$ by $c$ then
$$bd^2+bc^2=b(c^2+d^2)=0$$
So, either $c=d=0$ or $b=0$. Take the second case then we get $ac=0$ and $ad=0$. So either $a=0$ or $c=d=0$. The second option brings us back to our first case.