Because, by definition, $$r'(t) = \lim_{dt\to 0}\frac{r(t+dt)-r(t)}{dt}$$ This means that, for very small $dt$, $r'(t)\approx\frac{r(t+dt)-r(t)}{dt}$; that's just how one interprets limits. In other words, $r'(t) dt \approx r(t+dt)-r(t)$.
As a similar use of this reasoning: $e=\sum_{n=0}^\infty\frac{1}{n!}$, and so $e\approx \sum_{n=0}^N \frac{1}{n!}$ for very large $N$.