The chord that is one side of the pentagram subtends an angle of $\frac {4\pi}5$. If you draw the radii to the endpoints of the chord and a radius that bisects the chord you get two right triangles. The hypotenuse is the radius of the circle, $\frac {15.625}{2\pi}$. The angle of the triangle at the center is $\frac {2\pi}5$. The side opposite the angle at the center, which is half the chord, is $\frac {15.625}{2\pi}\sin \left(\frac {2\pi}5\right).$ The chord is twice this, $\frac {15.625}{\pi}\sin \left(\frac {2\pi}5\right)\approx 4.73.$
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