The probability of winning one game during a given set (and hence winning the set) is $1 - (1/2)^5$. The probability of winning ten sets in a row is therefore $(1-(1/2)^5)^{10} = 0.727...$.
**NB** I assume the outcome of all games are independent.
The probability of winning one game during a given set (and hence winning the set) is $1 - (1/2)^5$. The probability of winning ten sets in a row is therefore $(1-(1/2)^5)^{10} = 0.727...$.
**NB** I assume the outcome of all games are independent.