Yes, you can. If $\\{e_\alpha:\alpha\in I\\}$ is an orthonormal basis, then $\\{\lambda e_\alpha:\alpha\in I\\}$ is a tight frame with constant $A=\lambda^2$: $$ \sum_\alpha |\langle v,\lambda e_\alpha \rangle|^2 = \lambda^2\sum_\alpha |\langle v, e_\alpha \rangle|^2 = \lambda^2\|v\|^2 $$