$${a\over b-1}\gt \frac{a+1}{b+1}$$
$$ab+a\gt ab+b-a-1\implies b\lt 2a+1$$
If $b$ is less than $2a+1$ the first is better. If it is equal, both options are equal. If it is more, then, the second option is better.
$${a\over b-1}\gt \frac{a+1}{b+1}$$
$$ab+a\gt ab+b-a-1\implies b\lt 2a+1$$
If $b$ is less than $2a+1$ the first is better. If it is equal, both options are equal. If it is more, then, the second option is better.