Since $AB$ is the diameter of the 2nd circle, $\angle AGB=\frac{\pi}{2}$. This means that $AG \perp BG$ which is the radius of the 1st circle.
Since $AB$ is the diameter of the 2nd circle, $\angle AGB=\frac{\pi}{2}$. This means that $AG \perp BG$ which is the radius of the 1st circle.