Probability of 1 number not getting spun in roulette for 243 spins? I would like to know what the chance in percentage is that a specific number doesn't get spung for 243 spins in a row. Can someone help me out here? Thanks.

Assuming that the roulette wheel has numbers $0$ through $36$ (i.e. $37$ possible outcomes), this probability is:

$$\big( \frac{36}{37}\big) ^{243} \approx 0.0013$$ (i.e. it's roughly $1$ in a $1000$ which, given the number of casino's and roulette wheels being spun each day, is surely a daily occurrence)

Here is WolframAlpha's answer%5E243) for more decimals

Assuming that the roulette wheel has a double $0$ as well (i.e. $38$ possible outcomes), this probability is:

$$\big( \frac{37}{38}\big) ^{243} \approx 0.0015$$