Using find with grep and pass the result to another grep I'm trying to use find to locate a file and the first grep will look for a pattern in that file. the result will be passed to a second grep like so `find /Dime/Lock_Room/ -name CDRV.txt -type f -mtime -1 -exec fgrep "Audience" {} \; -exec fgrep "Prime_Time" {} \;` > I'm getting 1584508620604,Audience,Lunchtime/14196_135 1584508620604,Audience,Early_afternoon/8824_188 1584508620604,Audience,Late_afternoon/20124_128 1584508620604,Audience,Prime_Time/45214_3514 1584508620604,Audience,Prime_Time/55096_4206 1584508620604,Audience,Graveyard/1800_256 1584508620604,Public,Prime_Time/148351_1251 1584508620604,Audience,Graveyard/1800_256 1584508620604,Public,Prime_Time/158521_19 > I'm looking for 1584508620604,Audience,Prime_Time/45214_3514 1584508620604,Audience,Prime_Time/55096_4206 **PS: I'm trying not to use pipe | with find**

A huge Thanks to George Vasiliou, both answers worked fine, Answer 2 is my choice.

> Answer 1

`find /Dime/Lock_Room/ -name CDRV.txt -type f -mtime -1 -exec bash -c 'fgrep "Audience <(fgrep "Prime_Time" $0)' {} \;`

> Answer 2

`find /Dime/Lock_Room/ -name CDRV.txt -type f -mtime -1 -exec awk '/Audience/ && /Prime_Time/' {} \;`