Note that if we are $1$ meter below the water, the intensity of light is $1-0.035=0.965$ the intensity at the surface.
If we submerge another meter, the intensity is $0.965\times 0.965=(0.965)^2$.
Continuing, if we are $x$ meters below the surface, the intensity is $(0.965)^x$.
We need to find $x$ such that $(0.965)^x=0.25$.
Proceeding, we find that at
$$x=\frac{\log(0.25)}{\log(0.965)}$$
the intensity is 25%.