Turning comment into an answer.
That is Cauchy's integral formula. The full formula is given by
$$f^{(n)}(z) = \frac{n !}{2 \pi i} \int_{C}\\! \frac{f(\zeta)}{(\zeta - z)^{n+1}} \mathrm{d}\zeta $$
Turning comment into an answer.
That is Cauchy's integral formula. The full formula is given by
$$f^{(n)}(z) = \frac{n !}{2 \pi i} \int_{C}\\! \frac{f(\zeta)}{(\zeta - z)^{n+1}} \mathrm{d}\zeta $$