1. A relation _on_ a singleton set is always confluent. If $M=\\{a\\}$ all we need to check is that $$(a\mathrel R a \land a\mathrel R a) \to \exists z \in M : (a\mathrel R z\land a \mathrel R z)$$ which is obviously true -- if the left-hand side is true, then $a$ itself works as $z$.
2. If $R$ is the identity relation, the left-hand side is $x=w_1\land x=w_2$, so the only relevant case to check the right-hand side for is $x=w_1=w_2$. In that case choosing $z=x$ obviously makes $w_1=z\land w_2=z$ true.