The way you worded that is a little strange.
I have an alternative approach.
Let $I$ be the event that a person is infected, $D$ be the event that a person develops the disease, and $\bar I, \bar D$, not those events. Then $$P(I\bar D)= P(\bar D|I)P(I) = (1-P(D|I))P(I) = (1-.30)(.5) = 0.35 = 35\%$$ where in the second step I used the product rule.